Question

Solve the following equation
sinx + √3 cosx = √2​

Answer 1

Answer:

root3cosx=root2-sinx

Squaring on both sides

3cos^2x=2+sin^2x-2root2sinx

3(1-sin^2x)=2+sin^2x-2root2sinx

3-3sin^2x=2+sin^2x-2root2sinx

1-4sin^2x=-2root2-sinx

4sin^2x-2root2sinx - 1

Y=sinx

4y^2-2root2y-1

Y=2root2+-root8+16/8

Y=2root2+-2root6/8

Y=root2+-root6/4

Sinx=root2+-root6/4

X=sin inverse (root2+-root6) /4 ans