Question

solve the following equation this equations is from RD Sharma book of class 9 Chapter 2 exponents of real numbers

Answer 1

this is the answer of your question
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Answer 2

here is your ans friend
$2 {}^{x + 3} = 4 {}^{x - 1} \\ 2 {}^{x} \times 2 {}^{3} = 4 {}^{x} \div 4 \\ 2 {}^{x} \times 2 {}^{3} = 4 {}^{x} \div 2 {}^{2} \\ 4 {}^{x} \div 2 {}^{x} = 2 {}^{3} \times 2 {}^{2} \\ (4 \div 2) {}^{x} = 2 {}^{5} \\ 2 {}^{x} = 2 {}^{5} \\ x = 5$