Question

solve the following equation using completing the square method

Answer 1

6x^2 -7x + 2 =0

6x^2 -7x = -2

dividing with 6 on both sides.so that coefficient of x^2 will be zero

x^2 -7x/6 = -2/6

complete the square by adding the square of one-half of the coefficient of x to both sides, 

x^2 -7x/6 +( 7/(6/2))^2= -2/6 + ( 7/(6/2))^2


x^2 -7x/6 +( 7/12))^2= -2/6 + ( 7/12)^2



x^2 -7x/6 +49/144 = -2/6 + ( 7/12)^2

x^2 -7x/6 +49/144 = -2/6 + 49/144

(x - 7/12)^2 = (-2(24) + 49)/!44

(x-7/12)^2 = 1/144

x-7/12 =√(1/144) = + or - 1/12

x - 7/12 = + 1/12 ; x - 7/12 = - 1/12

x = 1/12 + 7/12 = 8/12 ; x = - 1/12 + 7/12 = 6/12

x= 8/12 = 2/3 ; x=6/12 = 1/2

x= 2/3 or 1/2