Question

solve the following equations 1/2 Z-2=5​

Answer 1

Step-by-step explanation:

How to solve your question

Your question is

1

2

⋅

−

2

=

5

\frac{1}{2} \cdot Z-2=5

21⋅Z−2=5

Solve

1

Combine multiplied terms into a single fraction

1

2

−

2

=

5

\frac{1}{2}Z-2=5

21Z−2=5

1

2

−

2

=

5

\frac{1Z}{2}-2=5

21Z−2=5

2

Multiply by 1

1

2

−

2

=

5

\frac{1Z}{2}-2=5

21Z−2=5

2

−

2

=

5

\frac{Z}{2}-2=5

2Z−2=5

3

Add

2

2

2

to both sides of the equation

2

−

2

=

5

\frac{Z}{2}-2=5

2Z−2=5

2

−

2

+

2

=

5

+

2

\frac{Z}{2}-2+{\color{#c92786}{2}}=5+{\color{#c92786}{2}}

2Z−2+2=5+2

4

Simplify

Add the numbers

Add the numbers

2

=

7

\frac{Z}{2}=7

2Z=7

5

Multiply all terms by the same value to eliminate fraction denominators

2

=

7

\frac{Z}{2}=7

2Z=7

2

⋅

2

=

2

⋅

7

2 \cdot \frac{Z}{2}=2 \cdot 7

2⋅2Z=2⋅7

6

Simplify

Cancel multiplied terms that are in the denominator

Multiply the numbers

=

1

4

Z=14

Z=14

Solution

=

1

4