solve the following equations 1/2 Z-2=5
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4
Step-by-step explanation:
How to solve your question
Your question is
1
2
⋅
−
2
=
5
\frac{1}{2} \cdot Z-2=5
21⋅Z−2=5
Solve
1
Combine multiplied terms into a single fraction
1
2
−
2
=
5
\frac{1}{2}Z-2=5
21Z−2=5
1
2
−
2
=
5
\frac{1Z}{2}-2=5
21Z−2=5
2
Multiply by 1
1
2
−
2
=
5
\frac{1Z}{2}-2=5
21Z−2=5
2
−
2
=
5
\frac{Z}{2}-2=5
2Z−2=5
3
Add
2
2
2
to both sides of the equation
2
−
2
=
5
\frac{Z}{2}-2=5
2Z−2=5
2
−
2
+
2
=
5
+
2
\frac{Z}{2}-2+{\color{#c92786}{2}}=5+{\color{#c92786}{2}}
2Z−2+2=5+2
4
Simplify
Add the numbers
Add the numbers
2
=
7
\frac{Z}{2}=7
2Z=7
5
Multiply all terms by the same value to eliminate fraction denominators
2
=
7
\frac{Z}{2}=7
2Z=7
2
⋅
2
=
2
⋅
7
2 \cdot \frac{Z}{2}=2 \cdot 7
2⋅2Z=2⋅7
6
Simplify
Cancel multiplied terms that are in the denominator
Multiply the numbers
=
1
4
Z=14
Z=14
Solution
=
1
4
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