solve the following equations
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Step-by-step explanation:
=√3-x/2+x +3 √2+x/3-x=4
=(√3-x/2+x × 2+x/3-x) +3 =4
=1/1×1/1+3=4 (3 is cancelled with 3 , 4 is cancelled with 4 , then both x is cancelled with both x, so only 1 remained)
=1+3=4
=4=4
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Answer:
26x^2 + 14x - 51 = 0
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