Question

solve the following equations:
2x+13=(-7) , 3a-5=16 , -2x+3=7 , 15-4a=3 , x/2-3=-5 , 16-x/3=15​

Answer 1

Answer:

hope it helps you

Step-by-step explanation:

1)2x+13 = -7

or, 12x = -7-13

x = -20/12

= - 5/3

2)3a-5 =16

or, 3a = 16+5

or, a=21/3

=7

3)-2x+3 = 7

or, -2x= 7-3

x = -4/2

= - 2

4)15 - 4a =3

or, -4a = 3 - 15

or, a =12/4

=3

5) x/2-3=5

or, x/2=5+3

or, x = 8×2

=16

6) 16-x/3=15

or, -x/3 =15 -16

or,x = 3

Answer 2

Answer:

$2x + 13 = - 7 \\ 2x = - 7 - 13 \\ 2x = - 20 \\ x = \frac{ - 20}{2} \\ \boxed{x = \underline{ \underline{- 10}}} \\ \\ 3a - 5 = 16 \\ 3a = 16 + 5 \\ 3a = 21 \\ a = \frac{21}{3} \\ \boxed{a = \underline{ \underline{7}}} \\ \\ - 2x + 3 = 7 \\ - 2x = 7 - 3 \\ - 2x = 4 \\ x = \frac{4}{ - 2} \\ \boxed{x = \underline{ \underline{- 2}}} \\ \\ 15 - 4a = 3 \\ - 4a = 3 - 15 \\ - 4a = - 12 \\ a = \frac{ - 12}{ - 4} \\ \boxed{a = \underline{ \underline{3}}} \\ \\ \frac{x}{2} - 3 = 5 \\ \frac{x}{2} = 5 + 3 \\ \frac{x}{2} = 8 \\ x = 8 \times 2 \\ \boxed{x = \underline{ \underline{16}}} \\ \\ 16 - \frac{x}{3} = 15 \\ 16 - 15 = \frac{x}{3} \\ 1 = \frac{x}{3} \\ 1 \times 3 = x \\ \boxed{\underline{ \underline{3}} = x}$