Question

Solve the following equations - (a) 5y/2 + 3 = 28 (b) 4n - 19 = 1​

Answer 1

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$\frac{5y}{2} + 3 = 28$

$\frac{5y}{2} = 28 - 3$

$\frac{5y}{2} = 25$

$5y = 25 \times 2$

$5y = 50$

$y = \frac{50}{5}$

$y = 10$

Answer 2

$(a) \: \: \frac{5y}{2} + 3 = 28 \\ \\ \\ \frac{5y + 6}{2} = 28 \\ \\ 5y = 56 - 6 = 50 \\ \\ \\ y = \frac{50}{10} = 5 \\ \\ \\ \\ \\ \\ (b) \: \: 4n - 19 = 1 \\ \\ 4n = 1 + 19 = 20 \\ \\ \\ n = \frac{20}{4} = 5$