Math, asked by aaban0, 2 months ago

Solve the following equations and check your result in each case.1/3(4x-1)+2/5(2x+5)-514/15=0​

Answers

Answered by goyalshraddha2581
1

Answer:

1/3(4x-1)+2/5(2x+5)-514/15=0

Domain of the equation: 3(4x-1)!=0

x∈R

Domain of the equation: 5(2x+5)!=0

x∈R

We calculate fractions

(75x2/(3(4x-1)*5(2x+5)*15)+(90x4/(3(4x-1)*5(2x+5)*15)+(-7710x^24/(3(4x-1)*5(2x+5)*15)=0

We calculate terms in parentheses: +(75x2/(3(4x-1)*5(2x+5)*15)+(90x4/(3(4x-1)*5(2x+5)*15)+(-7710x^24/(3(4x-1)*5(2x+5)*15), so:

75x2/(3(4x-1)*5(2x+5)*15)+(90x4/(3(4x-1)*5(2x+5)*15)+(-7710x^24/(3(4x-1)*5(2x+5)*15

We do not support expression: x^24

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