Question

solve the following equations. b+(b+1) + (b+2)/4 = 21​

Answer 1

$b + (b + 1) + \frac{b + 2}{4} = 21 \\ 2b + 1 + \frac{b + 2}{4} = 21 \\ \frac{8b + 4 + b + 2}{4} = 21 \\ 9b + 6 = 84 \\ 9b = 78 \\ b = \frac{78}{9}$

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Answer 2

Answer:

Step-by-step explanation:

(b+2)/4 =21 solutio 3*2 =21

but 2+1 =3