Question

solve the following equations by Cramer's method.
$6x - 3y = 10 \: and \: 3x + 5y - 8 = 0$
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Answer 1

Given,

6x - 3y = -10

3x + 5y - 8 = 0

arrange both equations in general form ax + by + c = 0 .

e.g., 6x - 3y + 10 = 0 -----(1)

3x + 5y - 8 = 0 -----(2)

now, use Cramer's rule,

=> x/(24 - 50) = -y/(-48 - 30) = 1/(30 +9)

=> x/-26 = -y/-78 = 1/39

=> x = -26/39 = -2/3 and y = 78/39 = 2

hence, x = -2/3 and y = 2