Math, asked by Nameera27, 3 months ago

Solve the following equations by factorisation method.
2 {x}^{2}  - 5x + 3

Answers

Answered by Anonymous
1

\huge{\red{\mathtt{\underline{Answer:}}}}

—»  2{x}^{2} - 2x - 3x + 3

—» \mathtt{ 2x(x-1)-3(x-1)}

—» \mathtt{(2x-3)(x-1)}

Answered by tinkurajanand
1

Answer:

x= 3/2 , 1

2x^2 - 5x+ 3

2x^2 - 2x - 3x + 3

2x (x-1) -3 (x-1)

(2x-3) (x-1)

Now we know that this is the factor of this equation

therefore,

2x-3=0

2x=3

x=3/2

and,,

x-1=0

x=1

Similar questions