Question

Solve the following equations by reducing them to quadratic equations:
✓4n-3 + √2n + 3 = 6​

Answer 1

Answer:

please mark me as Brainliest

Step-by-step explanation:

√4n + √2n +3 -3 = 6

=> √4n + √2n = 6

=> √4n + √2n -6 = 0

Solving by Sridharachariya Formula,

-b +- (√b^2 - 4ac)

n = -------------------------

2a

we get,

-√2n + √(√2n + 24√4n)

------------------------------------ ,

- √2n

-√2n - √(√2n + 24√4n)

------------------------------------

- √2n