Question

solve the following equations log (3x+2) + log(3x-2) =5 log 2​

Answer 1

Step-by-step explanation:

see carefully properties of log & see formula

Answer 2

Answer:

log(3x+2)+log(3x−2)=5log2

Let us simplify the expression,

log(3x+2)+log(3x−2)=log2  5

 

log[(3x+2)×(3x−2)]=log32

log(9$x^{2}$  −4)=log32

(9$x^{2}$ −4)=32

9$x^{2}$=32+4

9$x^{2}$ =36

$x^{2}$ =36/9

$x^{2}$  =4

x= √ 4

​ x=2

Step-by-step explanation: