Math, asked by chicheTDOS, 10 months ago

Solve the following equations on joint and combined variation.
1. y varies jointly as x and z. If y = 5 when x = 3 and z = 4, find y when x = 6 and z = 8.

2. y varies jointly as x and z. If y = 12 when x = 4 and z = 3, find y when x = 9 and z = 8.

3. y varies directly as x and inversely as z. If y = 5 when x = 3 and z = 4, find y when x = 6 and z = 8.

4.y varies directly as x^2 and inversely as z. If y = 12 when x = 2 and z = 7, find y when x = 3 and z = 9.

5. A varies jointly as b and h. If A = 16 when b = 2 and h = 8, find A when b = 8 and h = 16.

6. y varies jointly as x and the square root of z . If y = 6 when x = 3 and z = 9, find y when x = 4 and z = 36.

7. y varies jointly as the cube root of x and the square of z . If y = 3 when x = 8 and z = 4, find y correct to 3 significant figures, when x = 27 and z = 6.

8. y varies directly as x and inversely as z. If y = 10 when x = 9 and z = 12, find y correct to two decimal places, when x = 16 and z = 10.

9.x varies jointly as y^3 and square root of z . If x = 7 when y = 2 and z = 4, find x correct to 2 decimal places, when y = 3 and z = 9.

10. x varies jointly as y^3 and inversely as the square root of z . If x = 7 when y = 2 and z = 4, find x when y = 3 and z = 9.

Answers

Answered by divyanjali714
2

\frac{40}{3}Solution:

1. y=kxz (where k is a constant number)

5=k×3×4

k=\frac{5}{12}

then, y=\frac{5}{12}×6×8

         y=20

2. y=kxz (where k is a constant number)

12=k×4×3

k=1

then, y=1×9×8

         y=72

3. y=k×\frac{x}{z} (where k is a constant number)

5=k×\frac{3}{4}

k=\frac{20}{3}

then, y=\frac{20}{3}×\frac{6}{8}

        y=5

4. y=k×\frac{x^{2} }{z}  (where k is a constant number)

12=k×\frac{4}{7}

k=21

then, y=21×\frac{9}{9}

        y=21

5. A=kbh  (where k is a constant number)

16=k×2×8

k=1

then, A=1×8×16

         A=128

6. y=kx\sqrt{z}  (where k is a constant number)

6=k×3×3

k=\frac{2}{3}

then, y=\frac{2}{3}×4×6

        y=16

7. y=k\sqrt[3]{x}z^{2}   (where k is a constant number)

3=k×2×16

k=\frac{3}{32}

then, y=\frac{3}{32}××3×36

        y=\frac{324}{32}

8. y=k\frac{x}{z}  (where k is a constant number)

10=k\frac{9}{12}

k=\frac{40}{3}

then, y=  \frac{40}{3}×\frac{16}{10}

         y=\frac{64}{3}

9. x=ky^{3}\sqrt{z}   (where k is a constant number)

7=k×8×2

k=\frac{7}{16}

then, x=\frac{7}{16}×27×3

        x=2.21

10. x=k\frac{y^{3} }{\sqrt{z} }   (where k is a constant number)

7=k\frac{8}{2}

k=\frac{14}{8}

then, x=\frac{14}{8}×\frac{27}{3}

         x=\frac{63}{4}

#SPJ3

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