Solve the following equations on joint and combined variation.
1. y varies jointly as x and z. If y = 5 when x = 3 and z = 4, find y when x = 6 and z = 8.
2. y varies jointly as x and z. If y = 12 when x = 4 and z = 3, find y when x = 9 and z = 8.
3. y varies directly as x and inversely as z. If y = 5 when x = 3 and z = 4, find y when x = 6 and z = 8.
4.y varies directly as x^2 and inversely as z. If y = 12 when x = 2 and z = 7, find y when x = 3 and z = 9.
5. A varies jointly as b and h. If A = 16 when b = 2 and h = 8, find A when b = 8 and h = 16.
6. y varies jointly as x and the square root of z . If y = 6 when x = 3 and z = 9, find y when x = 4 and z = 36.
7. y varies jointly as the cube root of x and the square of z . If y = 3 when x = 8 and z = 4, find y correct to 3 significant figures, when x = 27 and z = 6.
8. y varies directly as x and inversely as z. If y = 10 when x = 9 and z = 12, find y correct to two decimal places, when x = 16 and z = 10.
9.x varies jointly as y^3 and square root of z . If x = 7 when y = 2 and z = 4, find x correct to 2 decimal places, when y = 3 and z = 9.
10. x varies jointly as y^3 and inversely as the square root of z . If x = 7 when y = 2 and z = 4, find x when y = 3 and z = 9.
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Solution:
1. y=kxz (where k is a constant number)
5=k×3×4
k=
then, y=×6×8
y=20
2. y=kxz (where k is a constant number)
12=k×4×3
k=1
then, y=1×9×8
y=72
3. y=k× (where k is a constant number)
5=k×
k=
then, y=×
y=5
4. y=k× (where k is a constant number)
12=k×
k=21
then, y=21×
y=21
5. A=kbh (where k is a constant number)
16=k×2×8
k=1
then, A=1×8×16
A=128
6. y=kx (where k is a constant number)
6=k×3×3
k=
then, y=×4×6
y=16
7. y=k (where k is a constant number)
3=k×2×16
k=
then, y=××3×36
y=
8. y=k (where k is a constant number)
10=k
k=
then, y= ×
y=
9. x=k (where k is a constant number)
7=k×8×2
k=
then, x=×27×3
x=2.21
10. x=k (where k is a constant number)
7=k
k=
then, x=×
x=
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