Solve the following equations without transposing and check your result. x + 5 = 9 (ii) y - 12 = -5 oth sides) (i) 3x + 4 = 19 (iv) 9z = 81 (v) 3x + 8 = 5x + 2 (vi) 5y + 10 = 4y – 10 Solve the following equations by transposing the terms and check your result. 2+ y = 7 (ii) 2a – 3 = 5 (ii) 10 - q = 6 (iv) 2t - 5 = 3 (v) 14 = 27 – x (vi) 5 (x+4) = 35 (vii ) -3x = 15 (vii) 5x -3 = 3x – 5 (ix 3y +4 = 5y-4 3 (x- 3) = 5 (2x + 1)
Answers
Answer:
Step-by-step explanation:
(I) x + 5 = 9
substract 5 from both sides to eliminate constant 5 on LHS
x + 5 - 5 = 9 - 5
x = 4
(ii) y - 12 = -5
add 12 on both sides to get rid of -12 in LHS
y - 12 + 12 = -5 + 12
y = -7
(iii) 3x + 4 = 19
subtract 4 on both side
3x + 4 - 4 = 19 - 4
3x = 15
divide by 3 on both sides
3x/3 = 15/3
x = 5
(iv) 9z = 81
divide by 9 on both sides
9z/9 = 81/9
z = 9
(v) 3x + 8 = 5x + 2
subtract 5x on both sides
3x + 8 - 5x = 5x + 2 - 5x
-2x + 8 = 2
Subtract 8 on both sides
-2x + 8 - 8 = 2 - 8
-2x = -6
divide by -2 on both sides
-2x/-2 = -6/-2
x = 3
(vi) 5y + 10 = 4y - 10
subtract 4y on both sides
5y + 10 - 4y = 4y - 10 - 4y
y + 10 = -10
Subtract 10 on both sides
y + 10 - 10 = -10 - 10
y = -20
with transposing
(I) 2 + y = 7
y = 7 - 2
y = 5
(Note: Give me a moment, I will send some attachments soon in the next edit. Typing them is a bit hard and time consuming)
Edit:- attached the attachments
hope this helps ☺️
Step-by-step explanation:
(ii)2a-3=5
sol: 2a-3=5
2a=8
a=4