Question

Solve the following equations: x(x+3)(x+4)(x+7)+32=0

Answer 1

$</p><p>xx+3x+4x+7 + 32 = \\ 0⇒xx+7x+3x+4 +32 \\ = 0⇒x2+7xx2+7x+12 + 32 \\ = 0 ⇒yy+12 + 32 = 0 </p><p></p><p>$

Answer 2

Answer: x=−6.372281,−5.561553,−1.438447,−0.627719

Step by step explanation :

x(x+3)(x+4)(x+7)+32=0

x4+14x3+61x2+84x+32=0

Step 1: Use quartic formula.

x=−6.372281,−5.561553,−1.438447,−0.627719