Math, asked by mayur3670, 7 months ago

Solve the following equations:
x+ y = a-b
ax+by=a²+ b²​

Answers

Answered by Sudhir1188
7

GIVEN:

  • x+y = a-b
  • ax+by = a²+b²

TO FIND:

  • Value of 'x' and 'y'.

SOLUTION:

Case 1

=> x+y = a-b ......(i)

Multiplying both sides by 'a'.

=> ax+ay = a²-ab ....(ii)

Case 2

=> ax+by = a²+b²

Multiplying both sides by 1.

=> ax+by = a²+b² ...(iii)

Subtracting eq(ii) from (iii)

=> (ax+by)-(ax+ay) = (a²+b²)-(a²-ab)

=> ax+by-ax-ay = a²+b²-a²+ab

=> by-ay = b(a+b)

=> y(b-a) = b(a+b)

=> y = [b(a+b)]/(b-a)

 putting \: y = \dfrac{b(a + b)}{(b - a)} \: in \: eq(i) \\  \\  \implies \: x +  \frac{ab + b {}^{2} }{b - a}    = a - b \\  \\  \implies \: x \:  = (a - b) -  \frac{ab + b {}^{2} }{b - a}  \\  \\  \implies \: x =  \frac{(a - b)(b - a) - ab - b {}^{2} }{b - a} \\  \\  \implies \: x \:  =   \frac{ab - a {}^{2}  - b {}^{2} + ab - ab - b {}^{2}  }{b - a}  \\  \\  \implies \: x =  \frac{ab - a {}^{2} - 2b {}^{2}  }{b - a}   \\  \\  \implies \: x \:  =  \frac{a {}^{2} + 2b {}^{2}  - ab }{a - b}

Answered by ushajosyula96
3

Answer:

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