Math, asked by Akash1413, 6 months ago

Solve the following equtions
15(y-4)-2(y-9)+5(y+6)=0

Answers

Answered by jagmeetfdk1998
0

=15y -60y-2y+18+5y+30

=20y-62y+48

= -42y+48

Answered by SparklingThunder
1

\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}

\small \textsf{Solve: 15 ( y -  4) - 2  ( y - 9) + 5 ( y + 6 ) = 0}

\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}

 \large\displaystyle { \color{red} \sf y =  \frac{2}{3} }

\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}

 \textsf{15 ( y -  4) - 2  ( y - 9) + 5 ( y + 6 ) = 0}

 \green{ \large \underline{ \mathbb{\underline{TO  \: FIND : }}}}

 \red{   \overline\textsf{\underline{Value of y .}}}

 \green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}

   \begin{array}{l} \\ \hline  \\ \small \sf{15 ( y -  4) - 2  ( y - 9) + 5 ( y + 6 ) = 0} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\   \\\small \sf15y - 60 - 2y + 18 + 5y + 30 = 0 \\  \\  \small \sf15y - 2y + 5y - 60 + 18 + 30 = 0 \\  \\ \small \sf13y + 5y - 60 + 48 = 0 \\  \\ \small \sf18y - 12 = 0 \\  \\ \small \sf18y = 12 \\  \\ \small  \displaystyle\sf y =  \frac{12}{18}  \\  \\ \small  \displaystyle\sf y =  \frac{2}{3}  \\   \\  \hline\\  \end{array}

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