Question

solve the following exponential equation
3^x=9(27^x)

Answer 1

Answer:x=-1

Step-by-step explanation:

3^x=9[(3)^3^x}

3^x=9x3^3x

3^x/3^3x=9

3^-2x=9

3^-2x=3^2

Bases same; Equate Powers

-2x=2

x=2/-2

x=-1

Hope it helped :D