Question

solve the following
Find the diagonala of a rectangle whose length is
16 cm and area is 192 sq.cm
​

Answer 1

Answer:

THE LENGTH OF DIAGONAL IS 20 CM.

Step-by-step explanation:

(Refering to the above diagram)

GIVEN, AREA=192 CM

LENGTH= 16 CM

LET BREADTH BE X

THEN,

AREA = 16×X= 192

X= 192/16

Z= 12 CM

LET. DIAGONAL BE D,

THEN, BY PYTHAGORAS THEOREM,

D²=

$\sqrt{16 {}^{2} + 12 {}^{2} }$

THEREFORE, BY SOLVING

D= 20 CM.

HOPE IT HELPS YOU.

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