Math, asked by yash11169, 1 year ago

solve the following for x:9x^2-9(a+b)x

Answers

Answered by Anonymous
4

Answer:


Step-by-step explanation:

9x²-9(a+b)x+(2a²+5ab+2b²)

first we will take 

(2a²+5ab+2b²)and factorize it

⇒2a²+4ab+ab+2b²

⇒2a(a+2b)+b(a+2b)

⇒(2a+b)(a+2b)

now,9x²-9(a+b)x+(2a+b)(a+2b)=0

9x²-3(2a+b)x-3(a+2b)x+(2a+b)(a+2b)=0

3x(3x-(2a+b))-(a+2b)(x-(2a+b))=0

(3x-(a+2b))(3x-(a+2b))=0

∴x=(a+2b)/3  and x=(2a+b)/3



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