Question

Solve the following:
If x:y=6:11,find (8x-3y):(3x+2y)​

Answer 1

Answer
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Given:
x:y=6:11
⇒x=6k, y=11k, where k is a constant.

Therefore,
(8x−3y):(3x+2y)=(8×6k−3×11k):(3×6k+2×11k)
=15k:40k
=3:

Answer 2

Answer:

37:40

Step-by-step explanation:

first of all put the values of x and y and then do the multiplication with the number of x and y to the given number and do subtraction of 2 numbers in 1st column nd addition of 2 numbers of 2nd column....then you got your answer....