Math, asked by bubu75, 1 month ago

solve the following in transposing method:- Robin, Naren, Shreya, Anubhav, Irfan and Paruma obtained marks in mathematics in the following manner- Shreya obtained two times of marks obtained by Naren, Anubhav obtained 5 marks less than marks obtained shreya, sum of the marks of irfan and naren is 105, robin obtained 5 marks less than marks obtained by paruma and paruma obtained 15 marks more than marks obtained by irfan. sum of their marks is 435. find the marks they have obtained, plz answer in details and quick replies, and plz do it correctly, plz, fast reply​

Answers

Answered by khandaregayatri113
1

Answer:

robin= 65 marks

Naren=50 mark

shrey=100

Anubhav=95

irfan=55

paruma=70 marks.

Similar questions