Math, asked by latheefbb, 5 months ago

Solve the following inequalities for real x
2x-3/4+8>=2+4x/3​

Answers

Answered by anurag2147
0

2x-3/4+8 ≥ 2+4x/3

= 2x-3/12 ≥ 2+4x/3

= 3(2x-3) ≥ 12(2+4x)

= 6x -9 ≥ 24 +48x

= 6x-48x ≥ 24+9

= -42x ≥ 33

= -x ≥ 33/42

= x ≤ 33/42

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