Question

5.
A particle moves along the X - axis
starting from x=+2m at t=0. At t=5s it
is at x=+8m and at t=12s it is at x=-12m.
The displacementof the particle in 12s.
1)-10 m 2) 8m 3) -14 m 4) 16 m​

Answer 1

Given,

The position of a particle moving along the x-axis is 2m, 8m, -12 at time 0s, 5s, and 12s.

To Find,

The displacement of the particle in 12s.

Solution,

Since we know that displacement of the particle is the shortest distance from start point to endpoint.

So, the start point was +2m and the endpoint was -12m.

Therefore, the total displacement of the particle is 14 m in negative x-direction = -14m.

Hence, the displacement of the particle in 12 s is -14 m.

Answer 2

The displacement of the particle is option (3) -14m

Explanation:

The displacement of the particle is given by change in position of the particle i.e. final position of the particle minus initial position of the particle.

Symbolically it is denoted by l.

Here in the given image we see that the initial coordinates of the particle is (0,2) and final coordinates are (12,-12) where 2 and -12 are the initial and final positions of the particle respectively.

Therefore l= (-12 i)-(2 i)

⇒l=-14i

Hence the magnitude of the displacement of the particle in 12 seconds is  option (3)  -14m