Question

Solve the following inequation : -2⅔ ≤ x+ ⅓ < 3+⅓ ; x ∈ R

Answer 1

Answer:

Given: −3(x−7)≥15−7x>

3

x+1

−3x+21≥15−7x>

3

x+1

⇒−3x+21≥15−7x and 155−7x>

3

x+1

⇒4x≥−6 and 45−21x>x+1

⇒x≥−

2

3

and 44>22x

⇒x≥

2

−3

and 2>x

∴ Solution set ={x:x∈R,

2

−3

≤x<2}