Question

Solve the following inequations : 5x-8/3 ≥ 4x-7/2, x∈R​

Answer 1

Step-by-step explanation:

, where x∈R.

10x−16≥12x−21

$= - 2x \geqslant - 5 = x \leqslant \frac{2}{5 }$

.

∴ solution set =(−∞, 2/5]

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Answer 2

Answer:

5x-8/3≥4x-7/2,x∈R

5x-4x≥-7/2+8/3

x≥-42/6+48/6

x≥8/6

x≥4/3 or x≥1•33