Question

solve the following linear equation for the unknown variable and verify the solutions 3y-5/5 -2(y-5)=y-1/2
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Answer 1

Answer:

Hope it's helpful for you ✌✌

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given :-

[(3y-5)/5] - [2(y-5)] = (y-1)/2

To find :-

Find the value of y ?

Solution :-

Given equation is [(3y-5)/5] - [2(y-5)] = (y-1)/2

=> [(3y-5)-(2×5(y-5))] /5 = (y-1)/2

=> [(3y-5)-10(y-5)]/5 = (y-1)/2

=> (3y-5-10y+50)/5 = (y-1)/2

=> (-7y+45)/5 = (y-1)/2

On applying cross multiplication then

=> 2(-7y+45) = 5(y-1)

=> -14y+90 = 5y-5

=> -14y-5y = -5-90

=> -19y = -95

=> 19y = 95

=> y = 95/19

=> y = 5

Therefore , y = 5

Answer:-

The value of y for the given problem is 5

Check:-

If y = 5 then LHS of the equation

[(3y-5)/5] - [2(y-5)]

=> [3×5-5)/5] -[2(5-5)]

=> [(15-5)/5]-[2(0)]

=> (10/5)-0

=> 2

RHS = (y-1)/2

=> (5-1)/2

=> 4/2

=> 2

LHS = RHS is true for y = 5

Verified the given relations in the given problem.