Question

solve the following linear equation x+3y-4=0,y+2x=6​

Answer 1

Answer:

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Step-by-step explanation:

so let x+3y-4=0 ie x+3y=4 (1)

2x+y=6 (2)

so multiplying (1) by 2

we get 2x+6y=8 (3)

subtracting (2) from (3)

we get

2x+6y=8

2x+y=6

(-) (-) (-)

________

5y=2

thus y=2/5=0.4

substitute value of y in any of three equations

we get x=2.8

hence (x,y)=(2.8,0.4) is solution of above linear equations