Question

X+6y+1=0,2x+3y+8=0 substitution

Answer 1

Step-by-step explanation:

x+6y=-1

x=-1-6y----(1)

2x+3y=-8------(2)

(1). in (2).

2(-1-6y)+3y=-8

-2-12y+3y=-8

-9y=-8+2=-6

y=2/3.-----(3)

Now, (3) in (1),

x=-1-6(2/3)

=-1-12/3

=-3-12/3

=-15/3

x=-5.

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Answer 2

The required solution x = - 5 , y = 2/3

Given :

The equations x + 6y + 1 = 0 , 2x + 3y + 8 = 0

To find :

The solution using substitution method

Solution :

Step 1 of 2 :

Write down the given system of equations

Here the given system of equations are

x + 6y + 1 = 0 - - - - - - - (1)

2x + 3y + 8 = 0 - - - - - - (2)

Step 2 of 2 :

Solve using substitution method

From Equation 1 we get

x = - 6y - 1 - - - - - - (3)

Substituting the value of y in equation (2) we get

$\displaystyle \sf 2( - 6y - 1) + 3y + 8 = 0$

$\displaystyle \sf{ \implies } - 12y -2 + 3y + 8 = 0$

$\displaystyle \sf{ \implies } - 9y + 6= 0$

$\displaystyle \sf{ \implies } 9y = 6$

$\displaystyle \sf{ \implies }y = \frac{6}{9}$

$\displaystyle \sf{ \implies }y = \frac{2}{3}$

Putting y = 2/3 in Equation 3 we get

$\displaystyle \sf x = - 6 \times \frac{2}{3} - 1$

$\displaystyle \sf{ \implies }x = - 4 - 1$

$\displaystyle \sf{ \implies }x = - 5$

Hence the required solution x = - 5 , y = 2/3

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