solve the following ordinary differential equation dy/dx+4xy=x
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dy/dx = x - 4xy
dy/dx = x(1-4y)
1/(1-4y).dy = xdx
(-1/4).(-4/(1-4y)) .dy=xdx
-1/4∫-4/(1-4y).dy=∫xdx
(-1/4)㏑(1-4y)=x²/2+c
dy/dx = x(1-4y)
1/(1-4y).dy = xdx
(-1/4).(-4/(1-4y)) .dy=xdx
-1/4∫-4/(1-4y).dy=∫xdx
(-1/4)㏑(1-4y)=x²/2+c
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