solve the following pair :-
3x-5y=4
2y+7=9x
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Given, 3x-5y-4=0
or, x = (5y + 4) / 3 (1)
9x = 2y + 7 (2)
Substituting eqn. (1) in eqn. (2), we get
9 (5y + 4) / 3 = 2y + 7
or, 3 (5y +4) = 2y + 7
or, 15y +12 -2y - 7= 0
or, 13y + 5 = 0
or, y = (- 5) / 13
so, x =(5(-5) / 13 + 4 ) / 3
x= 27/39
x = 9/13
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