Question

solve the following pair by substation method-0.2x+0.3y=1.3,0.4x+0.5y=2.3

Answer 1

this is the answer for the above question

Answer 2

let us assume
eqn 1 be 0.2x+0.3y=1.3
eqn 2 be0.4x+0.5= 2.3
first
multiple 10 in both eqns
you get
eqn 1*10= 2x+3y=13 this is 3 this is 3 eqn
eqn 2*10 = 4x+5y=23 this is 4eqn
multiple 2 in 3 eqn
4x+6y=26
4x+5y=23
y= 3
sub y=3 in 3 eqn
2x+3y=13
2x+ 3(3)=13
2x+9=13
2x=4
x=2
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