Question

Solve the following pair by using substitution method :

$\sqrt{2}x \: + \: \sqrt{3}y \: = 0 \\ \sqrt{3}x \: - \sqrt{8}y = 0$
Give full solution not only answer.
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Answer 1

√2x+√3y = 0 ---- i

√3x-√8y = 0. ---- ii

from eq ii

y = √3x/√8 ---- iii

substitute y in eq i

√2x+ √3(√3x/√8). = 0

√2x(√8) + 3x

√16x + 3x =0

4x+3x =0

7x=0

x= 0

on substituting x=0 in eq iii

y= √3×0/√8 =0

y=0

hence, x=0 , y=0

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