Question

Solve the following pair in substitution method. 4p+5q = 30; 6p +q = 19​

Answer 1

Explanation:

4p+5q=30

4p=30-5q

p=(30-5q)/4. (I)

now,

substitute (I) in equation 6p+q=19,we get

6p+q=19

6[(30-5q)/4]+q=19

3[(30-5q)/2]+q==19

(90-15q)/2+q=19

(90-15q+2q)/2=19

90-13q=38

-13q=38-90

-13q=-52

q=52/13

q=4. (ii)

again substitute(ii) in (I) ,we get

p =(30-5q)/4

p=(30-5×4)/4

p=(30-20)/4

p=10/4

p=5/2

hope it helps dear

Answer 2

Answer:

thanks

Explanation: