solve the following pair of equation by elimination method ×+2y =11 /2×-y=2
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Given,
x+2y=11. .........(i)
2x-y=2. .........(ii)
Multiply by 2 to eqn. (ii)
2(2x-y=2)
4x-2y=4. ..........(iii)
By elimination method,
Add equation (iii) and equation (i), we get
4x-2y=4
+ x+2y=11
5x =15
... x = 15/5
x=3
Put, x=3 in eqn.(i)
x+2y=11
3+2y=11
2y=11-3
y=8
2
Therefore, y=4
Hence, the value of x=3 and y=4.
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