Question

solve the following pair of equations by reducing them to a pair of linear equation 2/{x} x+3\{x} y=2,4\{x} x_9\{x} y=-1[/tex]

Answer 1

Answer:

(i)2x1 + 3y1

=2

3x1+ 2y1

=

6

13

Lets assume

x1

=p and y1

=q, both equations will become

2p + 3q

=2

⇒3p+2q=12 ... (A)

3p + 2q

= 6

13

⇒2p+3q=13 ...(B)

Multiply (A) by 3 and (B) by 2, we get

9p+6q=36

4p+6q=26

Subtracting these both, we get

5p=10

⇒p=2

⇒x= p1

= 21

∴q= 6

26−8

=3

⇒y= q1

= 31