Question

solve the following pair of equations by reducing them to a pair of linear equation: 5/x-1 + 1/y-2 = 2​

Answer 1

Answer:

REFER TO AS ATTACHMENT

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Answer 2

Answer:

5/(x-1) + 1/(y-2) - 2 =0 and

6/(x-1) - 3/(y-2) - 1 = 0. Let 1/(x-1) =a

and 1/(y-2)= b. The above equations become

5a + b - 2 = 0 ….(1)

6a -3b -1 = 0 …..(2). (1)×3 + (2) gives

21a -7 =0 => a = 7/21 = 1/3. Yang a= 1/3 in (2)

6(1/3)-3b -1 = 0 => 1–3b = 0 => b = 1/3

a = 1/3 => 1/(x-1) =1/3 => x-1=3 > x = 3+1=4

b =1/3 => 1/(y-2) =1/3 => y-2 =3 => y = 3+2=5

So x= 4, y = 5