Solve the following pair of equations by using the elimination method . (1) x-2y=3 , 3x-3y=5.
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Answer:
x-2y=3---eqn(1)
3x-3y=5----eqn(2)
eqn(1)×3; 3x-6y=9 (3)
3x-3y=5
(-) (+) (-)
subtract eqn (3)and (2)
therefore we will be left with
-3y=4 ;;so y=-4÷3
Now;
x-2y=3
x-2(-4÷3)=3
x+8÷3=3
x=3-8÷3
x=1÷3
x=-4\3; y=1/3
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I hope this will help you
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