Question

Solve the following pair of equations for x and y:
4/x + 3y = 8; 6/x - 4y = -5
Find the value of p such that y= px -8

Answer 1

Answer:

There are two equations :

4/x + 3y = 8 and 6/x - 4y = -5.

Let, 1/x = a and y = b.

So, we got

4a + 3b = 8 --------> (1)

6a - 4b = -5 --------> (2)

Now,

(1) × 4 => 16a + 12b = 32 ----->(3)

(2) × 3 => 18a -12b = -15 ----->(4)

Now let's add (3) and (4)

(3) + (4)

=> 16a + 12b + 18a - 12b = 32-15

=> 34a = 17

=> a = 1/2.

Now, putting a=1/2 in equation (1) we get,

=> 4×(1/2) + 3b = 8

=> 2 + 3b = 8

=> 3b = 6

=> b = 2.

Therefore,

=> 1/x = a. And => y = b.

=> 1/x = 1/2

=> x= 2.

Now ,putting the values of x and y on the equation given we get,

=> y = p(x) - 8

=> 2 = p(2) - 8

=> 2p = 2+8

=>2p = 10

=> p = 5.

SO, OUR REQUIRED ANSWER IS 【5】