solve the following pair of linear equation by reducing it to another pair with smaller coeffiecents:
31x+57y=150; 57x+31y=202
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I hope that the answer is correct.
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rashi61:
I'm in 9th and this type of questions are there in my book
thank you so much
that is because u r in ICSE
and i m in CBSE
board
ooooo
but if u need any other help from linear equation chapter i can help u out
hmmm
thnx
:-)
Answered by
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Answer:
31x+57y=150....................(1).
57x+31y=202...................(2).
Adding equation 1 and 2.
88x + 88y = 352.
88(x+y) = 352.
On solving the equation we get, x + y = 4.
Subtracting equation 1 and 2.
-26x + 26y = -52.
26(x - y ) = 52.
On solving we get.
x - y = 2.
Now solving the lower coefficients we get.
x+y=4.
x-y=2.
2x=6.
So, x=3 and y =1.
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