Solve the following pair of linear equation by substitution method: 2x + 3y = 13,4x + 5y =23
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2x + 3y = 13 ---(1)
4x + 5y = 23 ----(2)
from eq.1, we get
2x = 13 - 3y
=> x = (13 - 3y)/2 ---(3)
substituting the value of (3) in (2)
4(13-2y)/2 + 5y = 23
=>2(13 - 3y) + 5y = 23
=> 26 - 6y + 5y = 23
=> -y = 23 - 26
=> y = 3
substituting the value of y in (1)
2x + 3(3) = 0
=> 2x + 9 = 0
=> x = -9/2
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