Question

solve the following pair of linear equation by the substitution method 9x-10y= -12 ,2y+3y=13​

Answer 1

$9x - 10y = - 12...........(1) \\ 9x = - 12 + 10y \\ x = \frac{ - 12 + 10y}{9} ...........(2) \\ 2x + 3y = 13.............(3) \\ fill \: the \: value \: of \: (2) in(3)\\ 2( \frac{ - 12 + 10y}{9} ) + 3y = 13 \\ \frac{ - 24 + 20y + 27y}{9} = 13 \\ \frac{ - 24 + 47y}{9} = 13 \\ - 24 + 47y =11 7 \\ 47y = 117 + 24 \\ 47y = 141 \\ y = \frac{141}{47} \\ y = 3 \\ \: from(2) \\ x = \frac{ - 12 + 10(3)}{9} \\ x = \frac{ - 12 + 30}{9} \\ x = \frac{18}{9} \\ x = 2$

Hence, your answer is

x=2

y=3