Question

solve the following pair of linear equationby substitution and elimination method. 2x+3y=5 and 3x-2y=1​

Answer 1

Answer

x = 1 and y = 1

Solution

BY ELIMINATION METHOD

EQUATION:-

2x + 3y = 5 ....... (1)

3x - 2y = 1 ..........(2)

multiply equation (1) by 2

multiply equation (2) by 3

we get

=> 13x = 13

=> x = 1

=> put x = 1 in equation (1)

=> 2 (1) + 3y = 5

=> 3y = 3

=> y = 1

BY SUBSTITUTION METHOD

EQUATION:-

2x + 3y = 5 ...... (1)

3x - 2y = 1 ......(2)

From equation (2) we get:-

=> 3x - 2y = 1

=> 3x = 1 + 2y

=> x = 1 + 2y / 3 ...... (3)

put the value of x = 1 + 2y / 3 in equation (1)

=> 2 ( 1 + 2y ) / 3 + 3y = 5

=> 2 + 4y / 3 + 3y = 5

=> 13y = 15 - 2

=> 13y = 13

=> y = 1

put y = 1 in equation (3) we get:-

=> x = 1 + 2 (1) / 3

=> x = 3 / 3

=> x = 1