solve the following pair of linear equations
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3x + 4y=10
3x=10-4y
x=10-4y/3. (1)
2x-2y=2
sustituting x,in (1)
2(10-4y/3)=2
20-8y/3=2
4(5-2y/3)=2
2(5-2y)=0
-2y=-5
y=5/2
substituting y,in (1),
x=10-4*5/2/3
x=10-2*5/3
x=10-10/3
x=30-10/3
x=20/3
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