Question

Solve the following pair of linear equations by elimination method:
21x +47y - 110=0, 47x + 21y-162=0
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Answer 1

Answer:

given equation are

21x + 47y = 110 and 47x +21y =162

first add the both equation

we will get  68x +68y = 272

x +y = 4

then subtract the equation

we will get 26x - 26y = 52

x - y = 2

now add the getted equation

we will get 2x = 6

and x = 3

using the subtracted equation we get y = 1

hence x =3 and y = 1

Step-by-step explanation:

Answer 2

Answer

Hence,x=3,y=1 ,