Question

solve the following pair of linear equations by substitution method:. √3x+√5y=0
√5x-√8y=0

Answer 1

Answer:

Step-by-step explanation:

√3x + √5y = 0                                                             ....[1]

√5x - √8y = 0 ⇒ √5x = √8y  ⇒x=√8y/√5                ....[2]

By substituting x= √8/5×y, we get

√3[√8/5y] + √5y = 0⇒ √3[√8/5y]= -√5y

By squaring both side, we get

5y^2 = 3√[8/5]y^2⇒3y^2 = 5y^2/√8/5

3y^2= 5√5y^2/2√2⇒y^2=

Answer 2

Answer:

x = 0, y = 0

Step-by-step explanation:

refer the attachment below for your answer

hope it helps

@ana205