Question

The arch of a bridge has dimensions as shown, where the arch measure 2m at its highest point and its width is 6m. What is the radius of the circle that contains the arch?

Answer 1

Answer:

So, radius of our desired circle is 3.25m

Step-by-step explanation:

Given that

The height of the arch of the bridge = h = 2m

The width of the arch of the bridge  = w = 6m

In order to find the radius of circle which contain this arch we use the following formula:

r = $\frac{h}{2} + \frac{w^{2} }{8h}$

substituting values of h and w in the above formula

r = $\frac{2}{2} + \frac{6^{2} }{8x2}$

simplifying

r = 1 + $\frac{36}{16}$

r = 1 + 2.25

r = 3.25m

So, radius of circle which contain this arch is 3.25m.

Answer 2

Answer:

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