Question

solve the following pair of linear equations by substitution method 3x+2y-7=0 and 4x+y-6=0

Answer 1

3x=7-2y
x=7-2y/3
4x+y-6=0
4*7-2y/3+y=6
28-8y/3+y=6
28-8y+3y/3=6
28-5y=18
-5y=18-28
-5y=-10
y=-10/-5
y=2
x=7-2*2/3
=3/3
x=1
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Answer 2

Answer:

Step-by-step explanation:

Given That 3x+2y-7=0....... Equation I. And 4x+y-6=0...... Equation II. By Substitution Method. 3x+2y-7=0.

3x+2y=7

2y=7-3x

y=7-3x/2......III.

We Put The Value In Equation II

4x+y-6=0

4x+y=6.

4x+7-3x/2=6

8x+7-3x=12

8x-3x=12-7

5x=5

x=1....IV.

We Put The Value In Equation I

3x+2y=7

3(1)+2y=7

3+2y=7

2y=7-3

2y=4

y=4/2

y=2.

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