Math, asked by VEERMARAMJAT1979, 2 months ago

solve the following pair of linear equations by suitable method. 3x-y=3 and 5x-2y=4​

Answers

Answered by yuvraj2477
0

Answer:

Hello Sir You will get u r answer here only

Step-by-step explanation:

3x-y=3 (1)

5x-2y=4 (2)

Multiple equation 1 by 2 and equation 2 by 1

6x-2y=6

5x-2y=4

Now subtract these equations.

x=2

Therefore y = 6-12/-2

y = -6/-2 = 3

Your answer is x = 2 and y = 3.

Answered by Bᴇʏᴏɴᴅᴇʀ
16

Answer:-

\red{\bigstar} The values are

\large\leadsto\boxed{\tt\purple{x = 2}}

\large\leadsto\boxed{\tt\purple{y = 3}}

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Given:-

  • \sf 3x - y = 3 \dashrightarrow\bf\red{[eqn.i]}

  • \sf 5x - 2y = 4 \dashrightarrow\bf\red{[eqn.ii]}

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Solution:-

Firstly,

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Multiplying eqn.[i] by 2:-

\sf 3x - y = 3

\sf (3x - y = 3) \times 2

\sf 6x - 2y = 6 \dashrightarrow\bf\red{[eqn.iii]}

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Subtracting eqn.[ii] from [iii]:-

\sf (6x - 2y) - (5x - 2y) = 6 - 4

\sf 6x - 2y - 5x + 2y = 2

\sf 6x - 5x = 2

\large{\bf\pink{x = 2}}

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Substituting value of x in eqn.[i]:-

\sf 3x - y = 3

\sf 3 \times 2 - y = 3

\sf 6 - y = 3

\sf y = 6 - 3

\large{\bf\pink{y = 3}}

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Therefore, the values are

  • x = 2

  • y = 3
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